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Most of us learned the basics of music in elementary school.   The notes in music can be sung as:

Do - re - mi - fa - so - la - ti - do

There are even lyrics in The Sound of Music that most of us probably recognize:

Doe, a deer, a female deer
Ray, a drop of golden sun
.   .   .   .

But none of this tells us the actual frequencies of the notes.   To explain that, I'll go into a little more detail.   The notes in do - re - mi etc. can also be expressed as
 
 
(1)
  C - D - E - F - G - A - B - C  
  Where each note increases in pitch, until the second C, which is double the frequency of the first.   The second C is one octave higher than the first.   This is one definition of an octave – the same note, but double the frequency.

Now C - D - E etc. does not list all of the notes.   There are also flats and sharps.   So the complete list of notes is:
 
 
(2)
C - C# - D - D# - E - F - F# - G - G# - A - A# - B - C  
  Where # denotes sharp (so that C# is C sharp, D# is D sharp, A# is A sharp, and so on).   The reason I haven't written down E# is that E# is the same as F.   And B# is the same as C.   I could just as well have written:  
 
(3)
C - Db - D - Eb - E - F - Gb - G - Ab - A - Bb - B - C  
  Where b denotes flat (so that Eb is E flat and Bb is B flat, etc.)   And just as B# is the same as C, Cb is the same as B.

Earlier I said that second C in our sequence of notes was twice the frequency of the first C.   There is no reason to stop there.   I could go up another octave from the second C, or go down another from the first.

But before I do that, I can ask:   If the second C is twice the frequency of the first, how are the frequencies of C and D (or C and C#, or C and E, or any two notes) related?
 
  TOP  
 
 
Let's try the following.   I know C# has a higher frequency than C, but not double the frequency (since the second C in our list of notes is just double the frequency of our first C).   Suppose there is some number N, that when I multiply the frequency of the first C by N, I get the frequency of C#.   So, in terms of frequency:
 
 
(4)
  C#   =   N x C  
  I don't know what N is, but I'm hoping to come up with some reasoning that will tell me what it is.   Now suppose that the frequency D is related to that of C# in the same way:  
 
(5)
  D   =   N x C# I can combine (4) and (5):  
 
(6)
  D   =   N x C#   =   N x N x C   =   N2 x C    
  Suppose that D# and E can be written in a similar way:  
 
(7)
  D#   =   N x D   =   N2 X C#   =   N3 x C   and
 
(8)
  E   =   N x D#   =   N2 x D   =   N3 x C#   =   N4 x C
  Now, finally, we can write:  
 
(9)
  F   =   N x E       F#   =   N x F     G   =   N x F#       G#   =   N x G    
  A   =   N x G#       A#   =   N x A     B   =   N x A#       C2   =   N x B    
  Here I have referred to the second C as C2, to distinguish it from the first C, which I will now call C1.   I can now combine all of the expressions in (4) through (9):  
 
(10)
  C2   =   N x B   =   N2 x A#   =   N3 x A =   N4 x G#   =   N5 x G   =   N6 x F#
  =   N7 x F   =   N8 x E   =   N9 x D# =   N10 x D   =   N11 x C#   =   N12 x C1
  Since C2   =   2 x C1   the number N is the twelfth root of 2.   I won't describe how to calculate this number, I'll just give its value:  
 
(11)
  N   =   1.059463094359 If you wish, you can multiply it out twelve times and see that it gives 2.
  What (11) means is that, given the frequency of any note on the guitar, I can figure out the frequency of all the others.   And that's what I do next.  
  TOP  
 
 
Recall that when I derived the value of N I referred to the first pitch of interest as C1, and the second pitch, an octave higher, as C2.   I can define another set of notes, an octave higher, ending in C3.   And I can define yet another set of notes, an octave higher, ending in C4.   So the frequency of C2 is double that of C1; the frequency of C3 is double that of C2, and the frequency of C4 is double that of C3.

To get the frequencies of notes in each octave I just use (5), (6), and (7).   According to Scientific Pitch Notation, the note middle C is C4 and A4 is 440 Hertz (cycles per second).   Since A3 is an octave below A4, and A2 is an octave below A3, this would make A2 110 Hertz.

Note:   This same reference states that A4 is the first A above C4, so that the notes in the fourth octave are:
 
 
(12)
  C4 - C#4 - D4 - D#4 - E4 - F4 - F#4 - G4 - G#4 - A4 - A#4 - B4 - C5  
  I can find the frequency of C5 from the frequency of A4 by using:  
 
(13)
  C5   =   N x B4   =   N2 x A#4   =   N3 x A4  
  Multiplying A4 (which is 440 Hz) by N3, where N is given by (11), yields a frequency of 523.26 Hertz.   This is C5; middle C is C4 which is half this or 261.63 Hertz.  
  TOP  
 
 
Table N contains the frequencies of all of the musical notes from C0 to B8, using (5), (6), and (7).   The notes on the guitar range from a low of E2 (which is 82.41 Hertz) on the open sixth string, to (on my diagram, which is for an acoustic guitar) a high of G5, which is 784 Hertz.   On an electric guitar you might be able to get to C5, which is 1046.51 Hertz.   And on the guitar, middle C is obtained by holding down the string on the first fret of the second string.

 
 
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